Mathematics

Question

the equation of a line?
passes through (-2,5) and is parallel to y-2/3x+1

would the answer be y=2/3x+19/3

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  • y - 5 = m[ x - ( - 2 ) ] is the "point-slope" form of your staright - line equations;
    y - 5 = m( x + 2 ) ;
    But,  your line is parallel to y = ( 2 / 3 )x + 1;
     m = 2 / 3;
    Finally, y - 5 = ( 2 / 3)( x +  2);
     y = 5 + ( 2 / 3)x + 4 / 3;
    y = ( 2 / 3 )x + 15 / 3 + 4 / 3 ;
    y = ( 2 / 3 )x + 19 / 3.