Can someone plsss help me in this.

Answer:

first you need to find how long the side of the ab triangle is

so to find it you use the reciprocal Pythagorean theorem c2= a2-b2

so a2 -b2 = 6*6-2*2 = 30

so now we now that the side of the ab traingle is the square root of 30

then to find x you use the reciprocal Pythagorean theorem again and it goes x2= 30-c2

so x2= 30 -1*1 = 29

x = the square root of 29

Step-by-step explanation:

that should do it

Answer:

[tex]x \ = \ \sqrt{31} \ \text{m}[/tex]

Step-by-step explanation:

Since both triangles are right triangles, we then can leverage the Pythagorean Theorem.

Let the length of hypothenuse of the smaller triangle be [tex]\gamma[/tex] , hence

                                                 [tex]\gamma^{2} \ = a^{2} \ - \ b^{2} \\ \\ \gamma^{2} \ = \ \left(6\right)^{2} \ - \ \left(2\right)^{2} \\ \\ \gamma^{2} \ = \ 36 \ - \ 4 \\ \\ \gamma^{2} \ = \ 32[/tex]

Subsequently,

                                               [tex]\gamma^{2} \ = \ c^{2} \ + \ x^{2} \\ \\ \gamma^{2} \ - \ c^{2} = \ x^{2} \\ \\ x^{2} \ = \ 32 \ - \ \left(1\right)^{2} \\ \\ x^{2} \ = \ 32 \ - \ 1 \\ \\ x^{2} \ = \ 31 \\ \\ x \ = \ \sqrt{31}[/tex]