1-4y^2 = 0 Solve the equation
Question
Solve the equation
2 Answer
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1. User Answers WarCrimesIncarnate
Answer: y = 1/2 or y = -1/2
Step-by-step explanation:
First move the 1 to the side with the 0
-4y^2 = -1 // -1 because when you move a number to the other side of the equation you have to multiply -1
Then divide by -4 on each side
y^2 = 1/4
square root each side
|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value
so the answer would be y = 1/2 or -1/2
to check just put it into the equation as y. Both work.
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2. User Answers silirobert15
EXPLANATION:
[tex]1-4y^2=0\\1^2-(2y)^2=0\\(1-2y)(1+2y)=0\\[/tex]
⇒ [tex]1-2y=0[/tex] or [tex]1+2y=0\\[/tex]
⇒ [tex]2y=1[/tex] or [tex]2y=-1\\[/tex]
⇒ [tex]y= \frac{1}{2}[/tex] or [tex]y=\frac{-1}{2}[/tex]
P/s: [tex]A^2-B^2=(A-B)(A+B)[/tex]
Ok done. Thank to me :>