Physics

Question

5 A photographer runs away from an angry rhino toward the safety of her Jeep What will happen? (Speeds and distances are shown below the image.)
O
O
o
- Photographer is 10 meters from the Jeep
--Photographer runs 6 meters per second,
-Rhinois 16 meters from the Jeep
-Rhino runs 8 meters per second
- The Jeep is not moving
o
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O A. The photographer will get to the Jeep before the rhino catches her
O B. The rhino will catch the photographer before she reaches the Jeep
O . The rhino and the photographer will reach the Jeep at the same time,
OD. More information is needed
5 A photographer runs away from an angry rhino toward the safety of her Jeep What will happen? (Speeds and distances are shown below the image.) O O o - Photogr

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  • Answer:

    A. The photographer will get to the jeep before the rhinocerous

    Explanation:

    Δv =  Δd/Δt

    we can rearrange for time

    Δt = Δd/Δv

    For the photographer:

    Distance is 10m and moves at 6m/s

    Δt = 10m/6m/s

    Δt = 1.67s

    For the rhinocerous

    Distance is 16m and moves at 8m/s

    Δt = 16m/8m/s

    Δt = 2.00s

    The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino