Chemistry

Question

Congratulations! You’ve recently received a promotion from work. Your new job is to fill rooms with certain gases. A room is found to measure 9.00 feet wide by 12.0 feet long and 10.0 feet high. Your first assignment is to fill this room with a gas that has a density of 0.88543 kg/m3. Unfortunately your boss is asking you to make the gas (if you know what I mean). How many grams of this gas are required to fill the room? (1m3 = 35.3147 ft3) (Round to the appropriate sig fig)

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  • The amount of gas required to fill the room is 27076.4 g

    To calculate the grams of the gas that will fill the room, we make use of the formula below

    ⇒ Formula:

    • D = m/V....................... Equation 1

    ⇒ Where:

    • D = Density of the gas
    • m = mass of the gas
    • V = Volume of the room

    ⇒ make m the subject of the equation

    • m = DV................... Equation 2

    From the question,

    ⇒ Given:

    • D = 0.88543 kg/m³
    • V = Volume of a cubiod = Length×Width×Height = 9×12×10 = 1080 ft³

    ⇒ Converting the volume from ft³ to m³

    • V = 1080/35.3147
    • V = 30.58 m³

    Substitute these values into equation 2

    • m = 0.88543(30.58)
    • m = 27.0764 kg
    • m ≈ 27076.4 g

    Hence, The amount of gas required to fill the room is 27076.4 g

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