When Earth and the Moon are separated by a distance of 3.84 × 10^8 meters, the magnitude of the gravitational force of attraction between them is 2.0 × 10^20 ne
Physics
kimeH4anzalexygirl
Question
When Earth and the Moon are separated by a
distance of 3.84 × 10^8 meters, the magnitude of
the gravitational force of attraction between
them is 2.0 × 10^20 newtons. What would be the
magnitude of this gravitational force of attraction
if Earth and the Moon were separated by a
distance of 1.92 × 10^8 meters?
(1) 5.0 × 10^19 N (3) 4.0 × 10^20 N
(2) 2.0 × 10^20 N (4) 8.0 × 10^20 N
distance of 3.84 × 10^8 meters, the magnitude of
the gravitational force of attraction between
them is 2.0 × 10^20 newtons. What would be the
magnitude of this gravitational force of attraction
if Earth and the Moon were separated by a
distance of 1.92 × 10^8 meters?
(1) 5.0 × 10^19 N (3) 4.0 × 10^20 N
(2) 2.0 × 10^20 N (4) 8.0 × 10^20 N
2 Answer
File Size: 23.8 MB
File Type: PDF / ePub
Uploaded on: 20240118 05:10:00
READ ANOTHER ANSWER
Last checked: 1 hours 14 minutes ago!
Rating: 4.6/5 from 2955 votes.

1. User Answers Anonym
Using the Universal Gratitation Law, we have:
[tex]F= \frac{MmG}{d^2} \\ MmG=2*10^{20}*(3.84*10^8)^2 \\ MmG=29.4912*10^36[/tex]
Again applying the formula in the new situation, comes:
[tex]F= \frac{MmG}{d^2} \\ F= \frac{29.4912*10^36}{(1.92*10^8)^2} \\ \boxed {F=8*10^{20}}[/tex]
Number 4
If you notice any mistake in my english, please let me know, because i am not native. 
2. User Answers AL2006
The strength of the gravitational forces between two masses is
inversely proportional to the square of the distance between them.
So if you change the distance to
(1.92 x 10⁸) / (3.84 x 10⁸) = 1/2
of what it is now, then you would change the force to
1 / (1/2)² = 4
of what it is now.
(4) x (2 x 10²⁰) = 8.0 x 10²⁰ newtons .