A 3.00newton force causes a spring to stretch 60.0 centimeters. Calculate the spring constant of this spring. [Show all work, including the equation and substi
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1. User Answers TaylorBayley
This is a question that utilises Hooke's law, F=kX where F is the magnitude of the force applied, k is the spring constant, and X is the displacement of the end of the spring from its relaxed position.
We know the force and X so we can rearrange to make k=F/X
Then, substitute the values for F and X.
k=3/0.6= 5 N/m 
2. User Answers ConcepcionPetillo
The spring constant k = 50 N/m
According to Hooke's Law, the restoring force F of a spring is:
F = kx
where k is the spring constant and x is the displacement after stretch.
Given that x = 60 cm = 0.6 m and F = 3 N
then, k = F/x = 3/0.6 N/m
k = 50 N/m is the spring constant
Learn more about Hooke's Law:
https://brainly.com/question/14904214